In the given figure if AB||CD then the value of 'x' is DO=2x-1 AO=5 BO=2x+4 CO=4x-2 a) 2 units
b) 4 units
c) 3 units
d) 5units
Answers
Answer:
In the given figure if AB||CD then the value of 'x' is DO=2x-1 AO=5 BO=2x+4 CO=4x-2 a) 2 u
d) 5units
Given :- In the given figure if AB||CD then the value of 'x' is DO=2x-1 AO=5 BO=2x+4 CO=4x-2
a) 2 units
b) 4 units
c) 3 units
d) 5units
Solution :-
since AB is parallel to CD . so, ABCD must be a trapezium .
we know that, in trapezium ,
- The diagonals of a trapezium divide each other proportionally .
so,
→ AO/CO = BO/DO
putting given values we get,
→ 5/(4x - 2) = (2x + 4)/(2x - 1)
→ 5(2x - 1) = (4x - 2)(2x + 4)
→ 10x - 5 = 8x² + 16x - 4x - 8
→ 8x² + 2x - 3 = 0
→ 8x² - 4x + 6x - 3 = 0
→ 4x(2x - 1) + 3(2x - 1) = 0
→ (4x + 3)(2x - 1) = 0
→ x = (-3/4) and (1/2) .
given options are not correct or data is not correctly written .
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