In the given figure if AB || DC find x. pls answer!!!
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Maybe this is right...
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seg AB || seg DC
On transversal AC
angle BAC = angle DCA [ alternate angles test ]
angle BAO = angle DCO ...... 1 [ A-O-C ]
in ∆AOB and ∆ COD ,
angle BAO = angle DCO [ from 1 ]
angle AOB = angle COD [ vertically opposite angles]
∆ AOB ~ ∆ COD [ AA test of similarity]
AO/CO = OB/OD = AB /CD (corresponding sides of similar traingles are in proportion)
x+5/x+3 = x-1 / x-2 = AB/CD (placing the given values )
x+5/x+3 = x-1 / x-2
(x-2)(x+5) = ( x+3)(x-1)
x²+5x -2x-10 = x² -x +3x-3
x²+3x-10= x²+2x -3
3x-2x = -3+10
x=7
= sign means congruent
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