Question

in the given figure if ab parallel to CD then angle FXE is equal to​

Answer 1

Answer:

Step-by-step explanation:

AB || CD,then FE is the transversal

Therefore, |_BFE= |_CEF

110°= |_BFX +|_XFE

110°= 50° + |_XFE

|_XFE=60°

|_CEF+ |_FEX+|_XED =180°

110°+|_FEX+30°= 180°

|_FEX=180°-140°

|_FEX=40°

In triangle FEX,

|_FEX+|_XFE+|_FXE=180°. (Angle sum property)

40°+60°+|_FXE=180°

|_FXE=180°-100°

Therefore....|_FXE=80°

Hence found

Hope it helps.....

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