Question

in the given figure If Angle AOB=70° then angle Acb is equal to.show working

Answer 1

Explanation:

In given figure,

Quadrilateral ABCD is a parallelogram.

So, AD ∣∣ BC

∴ ∠DAC = ∠ACB --- ( Alternate angle)

∴ ∠ACB = 32

∘

∠AOB + ∠BOC = 180

∘

--- (straight angle)

⇒70

∘

+ ∠BOC = 180

∘

∴ ∠BOC = 110

∘

In △BOC,

∠OBC + ∠BOC + ∠OCB = 180

∘

⇒∠OBC + 110

∘

+ 32

∘

= 180

∘

⇒ ∠OBC = 38

∘

∴ ∠DBC = 38

∘

Answer 2

Answer:

35° IS THE CORRECT ANSWER

EXPLANATION:-

<AOB = 2<ACB. (Angle at the center is double the angle at the circumference by the same chord)

70° = 2 <ACB

35° = <ACB