Question

In the given figure, if angle AOC + BOD= 266, find all the four angles​

Answer 1

Answer:

From figure,

Angle AOC= Angle BOD.......(opposite

angles)

Angle AOC+Angle BOD=266°

Angle AOC+Angle AOC=266°

2 Angle AOC=266°

Angle AOC=266°/2

Angle AOC=133°

Angle AOC+Angle BOC=180°...(angles in

linear pair)

133°+Angle BOC=180°

Angle BOC=180°-133°

Angle BOC=47°

Angle AOC=133°

Angle BOC=47°

Angle BOD=133°

Angle AOD=47°

Answer 2

Answer:

Step-by-step explanation:

angle AOD = BOC

Let angle AOD = BOC = x

In the give figure,

angle AOD + angle BOC +angle AOC + angle BOD = 360° (angle sum property)

x + x + 266° = 360°

2x = 360° - 266°

2x = 94°

x = 47°

angle AOD = angle BOC = 47°

angle AOC + angle BOC = 180° (Linear Pair)

angle AOC + 47° = 180°

angle AOC = 133°

angle BOD = 133° (vertically opposite angle)

Hope it will help you. ...