In the given figure if angle PTQ=50°. Find angle POQ
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12
The answer goes like this:
90°+90°+50°+POQ=360°
180°+50°+POQ=360°
POQ=360°-230°
POQ=130°
90°+90°+50°+POQ=360°
180°+50°+POQ=360°
POQ=360°-230°
POQ=130°
travelneeds:
360°-230°=130°
Answered by
6
Answer:
Step-by-step explanation:
PT and TQ are tangents and radius of a circle is perpendicular to tangents
So,
∠OPT=∠OQT=90°
OPTQ is a quadrilateral
So,
∠O+∠P+∠T+∠Q=360°
∠O+90°+50°+90°=360
∠O=360-230
⇒∠POQ=130°
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