Question

In the given figure, if AOB is a line then find the
measure of BOC, COD and DOA​

Answer 1

Answer:

DOA+DOC+COB=180(Linear pair angles)

5y+3y+2y=180

10y=180

y=18

DOA=5*18=90

COD=3*18=54

BOC=2*18=36

Answer 2

❥${\purple{\underline{\underline{\large{\mathtt{ANSWER:-}}}}}}$

• angle DOA = 90°
• angle COD = 54°
• angle BOC = 36°

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❥${\purple{\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}}$

•Given:-

• AOB is a straight line.
• angle DOA= 5y.
• angle COD = 3y.
• angle BOC = 2y.

•To find:-

• Measure of three angles.

•Solution:-

$\sf{We\: know,}$

$\sf{\green{AOC=180\: degrees [AOC\:is\:a\: straight\:line]}}$

According to the question,

angle (DOA+COD+BOC)=180°

→5y+3y+2y = 180°

→10y = 180°

→y = 18°

Now , find these three angles.

• angle DOA = 5×18° = 90°
• angle COD = 3×18° = 54°
• angle BOC = 2×18° = 36°

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❥${\underline{\underline{\large{\mathtt{VERIFICATION:-}}}}}$

• angle DOA = 90°
• angle COD = 54°
• angle BOC = 36°

By adding,

90°+54°+36° = 180°

→180° = 180° (Verified)

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