Question

In the given figure, if BC is the diameter of the circle reasons) of angle BCD, angle BDA and angle BAD and AB = DA , angle DBC=40^ . Find the measure (with 5.0 40 ^ 2 B​

Answer 1

Answer:

∠BCD = 45° if in given figure, BC is a diameter of the circle and AD bisects angle BAC. Step-by-step explanation: ∠BCD = ∠BAD ( angle formed by ...

Top answer · 1 vote

∠BCD = 45° if in given figure, BC is a diameter of the circle and AD bisects angle BACStep-by-ste ... More

3 votes

angle BCD is 45°. because angle ACD IS 90 angle in a semicircle is 90bc bisect angle acd More

Answer 2

Answer:

→ABCD is a parallelogram

Therefore,

Angle A = Angle C = 70°

In ∆ BCD

Angle DBC + Angle C + Angle CDB =180° ( Angle Sum property of ∆)

→ Angle CDB = 180-70-80

→ Angle CDB = 30°

Now,

When, AB II BC And BC is the transversal

Therefore,

Angle ADB = Angle BDC

→Angle ADB = 80°