in the given figure if cd//ef and ab is a tranversal find the value of x and hence find the measure of angle ghe
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Step-by-step explanation:
It is given that,
AB // CD, EF is the transversal.
i) <CGH = <GHB [ alternate angles]
y = 3x ----(1)
<EGC + <CGH = 180° [ Linear angles ]
2x + y = 180---(2)
2x + 3x = 180 [ from (1)]
5x = 180
x = 180/5
x = 36°
Put x value in equation (1), we get
y = 3 x 36 = 108°
ii) <EGD = GHB [ Corresponding Angles]
2x + 15 = 3x - 20
15 + 20 = 3x - 2x
35=X
x = 35°
iii) <DGH + <DHB = 180°
[Sum of interior angles same side of the
transversal ]
4x 23 + 3x = 180°
7x = 180 + 23
7x = 203°
x = 203/7
65
X = 29°
I hope this helps you.
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