In the given figure, if chords AB and CD of the circle intersect each other at right angles then x+y=?
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Answer:
Answer is 90 use exterior angle property in PDB
Angle D is x only
Because Angle subtended by an arc at any part of circle is equal.
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x + y = 90°
Step-by-step explanation:
if chords AB and CD of the circle intersect each other at right angles then,
∴ ∠CAO = ∠ODB = x [angles in same segment ] ---- (i)
Now, in right angled ΔDOB ,
∠ODB + ∠DOB + ∠OBD = 180° (angle sum property)
we get
⇒ x + 90° + y =180° (using equation i)
⇒ x + y = 90°
hence ,
x + y = 90°
#Learn more:
Chords Ab and cd of a circle intersect each other at p such that AP =CD show that Ab =CD
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