Question

In the given figure if F = 30 N, the acceleration of both the
blocks is 1 m/s. The net frictional force acting on the blocks
is (10xk)N. Find the value of 'K'.​

Answer 1

$hey \\ here \: is \: the \: answer \\ \\ the \: force \: which \: is \: opposing \: friction \: will \: be \\ total \: force - force \: needed \: to \: move \: the \: blocks \\ \\ f = ma \\ f = (5 + 5)(1) \\ = 10 \: newton \\ \\ so \:the \: net \: frictional \: force \: will \: be \: \\ = 30 - 10 \\ = 20newton \\ so \: the \: value \: of \: k \: will \: be \\ 10k = 20newton \\ k = \frac{20}{10} \\ k = 2$

Answer 2

answer is 2 hope it helps