Question

The sum of three no. is 98.The ratio of the first to second is 2/3 and the ratio of the second to third is 5/8. Find the second number.

Answer 1

let the common multiple be x in ratio 1 hence 1st no 2x 2nd 3x

let the cmmn multiple be y in ratio 2 hence 2nd 5y 3rd 8y

but 3x=5y y=3/5x

2x+3x+8y=98

2x+3x+8(3/5x)=98

solve no own

Answer 2

Answer:

Step-by-step explanation:

Solution:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer: (c)