Question

In the given figure if line segment pq and rs intersect at point t such that angle pst=40 and angle rpt=95 and tsq=75 find angle sqt

Answer 1

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Answer 2

Hello mate ☺

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Solution:

In ∆PRT, we have

∠PRT+∠RPT+∠RTP=180°   (Sum of three angles of a triangle =180°)

⇒40°+95°+∠RTP=180°

⇒∠RTP=180°−40°−95°=45°

∠RTP=∠QTS     (Vertically Opposite Angles)

Therefore, ∠QTS is also equal to 45°

In ∆STQ, we have

∠SQT+∠TSQ+∠QTS=180°  (Sum of three angles of a triangle =180°)

⇒∠SQT+75°+45°=180°

⇒∠SQT=180°−75°−45°=60°

I hope, this will help you.☺

Thank you______❤

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