Question

In the given figure, if two chords PQ and RS of a circle with centre O intersect each other at M such that

PM = MS, then prove that MR = MQ.​

Answer 1

Step-by-step explanation:

For △PMS and △SMQ

1.∠PMR=∠QMS (Vertically opposite angle)

2.∠MPR=∠MSQ (Angle subtended by the same arc are equal)

3.∠MRP=∠MQS (Sum property of △).

Thus By AAA criteria △PMS ≈ △SMQ