Math, asked by rockstarrishabh2006, 8 months ago

In the given figure,
is the centre of the circle. Find the value of x​

Attachments:

Answers

Answered by kamathsulakshana23
1

X=30°

since ang.X = ang.B,

bcz... they are the angles subtended by the same chord

in ∆BDC,

ang[A + B + C] = 180°{angle sum prp.}

X + 2X + 90° = 180°

{angle c is subtended by simicircle, so it is a right angle}

3X = 90°

•°• X = 30°

thank you

hope it helps you.....

 &lt;style style="text/css"&gt;</p><p>.horizontally {</p><p> height: 50px;	</p><p> overflow: hidden;</p><p> position: relative;</p><p> background: yellow;</p><p> color: orange;</p><p> border: 1px solid orange;</p><p>}</p><p>.horizontally p {</p><p> position: absolute;</p><p> width: 100%;</p><p> height: 100%;</p><p> margin: 0;</p><p> line-height: 50px;</p><p> text-align: center;</p><p> /* Starting position */</p><p> -moz-transform:translateX(50%);</p><p> -webkit-transform:translateX(50%);	</p><p> transform:translateX(50%);</p><p> /* Apply animation to this element */	</p><p> -moz-animation: horizontally 5s linear infinite alternate;</p><p> -webkit-animation: horizontally 5s linear infinite alternate;</p><p> animation: horizontally 5s linear infinite alternate;</p><p>}</p><p>/* Move it (define the animation) */</p><p>@-moz-keyframes horizontally {</p><p> 0%   { -moz-transform: translateX(50%); }</p><p> 100% { -moz-transform: translateX(-50%); }</p><p>}</p><p>@-webkit-keyframes horizontally {</p><p> 0%   { -webkit-transform: translateX(50%); }</p><p> 100% { -webkit-transform: translateX(-50%); }</p><p>}</p><p>@keyframes horizontally {</p><p> 0%   { </p><p> -moz-transform: translateX(50%); /* Browser bug fix */</p><p> -webkit-transform: translateX(50%); /* Browser bug fix */</p><p> transform: translateX(50%); 		</p><p> }</p><p> 100% { </p><p> -moz-transform: translateX(-50%); /* Browser bug fix */</p><p> -webkit-transform: translateX(-50%); /* Browser bug fix */</p><p> transform: translateX(-50%); </p><p> }</p><p>}</p><p>&lt;/style&gt;</p><p></p><p>&lt;div class="horizontally"&gt;</p><p>&lt;p&gt;mark as the brainliest &lt;/p&gt;</p><p>&lt;/div&gt;</p><p>

Similar questions
Math, 4 months ago