In the given figure,
is the centre of the circle. Find the value of x
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X=30°
since ang.X = ang.B,
bcz... they are the angles subtended by the same chord
in ∆BDC,
ang[A + B + C] = 180°{angle sum prp.}
X + 2X + 90° = 180°
{angle c is subtended by simicircle, so it is a right angle}
3X = 90°
•°• X = 30°
thank you
hope it helps you.....
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