Question

in the given figure l is parallel to m and ABCD , BCFE and EFGH are parallelograms . Prove that area of parallelograms ABCD = area of parallelograms EFGH . Pls mention used theorems ​

Answer 1

Step-by-step explanation:

we know that parallel b/w same base and b/w same parallel have equal areas

so, ar||gm ABCD = ar||gm BCFE ( ON SAME BASE BC AND BETWEEN SAME PARALLEL)

BUT, ar||gm BCFE = ar||gm EFGH ( ON SAME BASE EF AND B/w SAME PARALLEL)

ON SUBSTITUTING THE VALUES,

ar|| ABCD = ar||EFGH

HENCE PROVED.....

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