Question

In the given figure l is parallel to m. and one angle is 40 degree find the value of x​

Answer 1

The value of $x$ is $50\ degree$

Step-by-step explanation:

Given,

In figure, $l\parallel m$ and $\angle CBA=40\ degree$

∵ $l\parallel m$

So, $\angle ACm=\angle CDl$

Lets,

$\angle ACm=\angle CDl=\theta$

From $\triangle ABC$, $Cm$ is the exterior line.

We know,

Any triangle Exterior angle is equal to the sum of two interior angle.

∴ $\angle CAB+\angle ABC=\angle ACm$

⇒$x+40=\theta$

⇒$x=\theta-40$

If the line $AD$ is perpendicular with line $m$ or $l$

Then,

$\angle ACm=\angle CDl=90\ degree$

Then,

⇒$x=90-40$

∴ $x=50\ degree$

So, The value of $x$ is $50\ degree$

Answer 2

Answer:

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