Question

In the given figure l||m and t is a transversal.If angle 1 and angle 2 are in the ratio 5:7,find the measure of each of the angles angle 1,2,3,8.
Plz explain​

Answer 1

Step-by-step explanation:

let angle 1=5x, angle 2=7x.

angle (1+2)=5x+7x=180°

reason....(angle 1 and 2 are linear pair).

=12x=180°

=x=15°

so , angle 1 is 5x=5×15°=75°

angle 2=7x=7×15°=105°

Now angle 3= angle 1=75°(vertically opposite angle)

angle 4=angle 2=105°(vertically opposite angle)

angle 6=angle 2= 105°(corresponding angle)

angle 5 = angle 1=75°( corresponding angle)

angle 8=angle 6=105°(v.o.s)

angle 7= angle 5=75°(v.o.s).

Answer 2

Hey mate here is your answer......

ratio of angle 1 and angle 2 = 5:7

angle 1 + angle 2 = 180 degree

reason -angle 1 and angle 2 are linear pair.

take the common multiple as x

so the equation will be-

5x+7x= 180

12x=180

x=180/12

x=15

so now we have found out that

angle 1 = 5x = 5 multiply 15=75

angle 2 = 7x = 7 multiply 15=105

In this way we have found out

angle 1=75

angle 2=105

Now we have to find angle 3 and 8

Angle 2 and 3 are in linear pair

So,

angle 2+ angle 3=180

105+ angle 3 =180

angle 3 = 180-105

angle 3 =75

angle 3 and 7 are corresponding pair

Therefore angle 7 = 75 degree

So,

angle 7 and angle 8 are linear pair

angle 8+ angle 7 =180 degree

angle 8 + 75=180

angle 8=180-75

angle 8 =105