in the given figure l parallel m find x
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Answered by
4
angle ABE +angleDEB =180° ( co-interior)
65°+ angle DEB =180
angle DEB =115 = y (V. O. A)
in triangle CEF
x +115+20 =180
x +135 =180
x =180-135
x= 45°
65°+ angle DEB =180
angle DEB =115 = y (V. O. A)
in triangle CEF
x +115+20 =180
x +135 =180
x =180-135
x= 45°
Answered by
2
Given--
/_B=65°
/_F=20°
So, /_B+/_E=180
65+/_E=180
/_E=180-65
/_E=115
Therefore,
y=115 (Vertically opposite angle)
=/_y+/_x+/_f=180
=115+/_x+/_20=180
=135+x=180
= x=180-135
=45°
/_B=65°
/_F=20°
So, /_B+/_E=180
65+/_E=180
/_E=180-65
/_E=115
Therefore,
y=115 (Vertically opposite angle)
=/_y+/_x+/_f=180
=115+/_x+/_20=180
=135+x=180
= x=180-135
=45°
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