Question

In the given figure, length of arc AB and arc B
are in the ratio 4:3. If ZAOB =96º, find

(i) Angle CAB
(ii) Angle ADB
Ans.: (i) 36° (ii) 132​

Answer 1

Answer:

AOB=96

0

AB

:

BC

=3:2

⇒∡AOB:∡BOC=3:2

⇒

∡BOC

96

0

=

2

3

⇒∡BOC=

3

2

×96

0

=64

0

Now, Δ

"

OBC is isosceles [∵ OB=OC=r]

∴ ∡BOC+2∡OBC=180

0

⇒∡OBC=

2

180−64

=58

0

also Δ

"

AOB is isosceles [because OA=OB=r]

∴ ∡AOB+2∡OBA=180

0

⇒∡OBA=

2

180−96

=42

0

∴ ∡ABC=58

0

+42

0

=100

0

solution

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