in the given figure length of arc AB is and length of arc BC are in ratio 3:2, if angle AOB=84 find
1. angle BOC
2. angle CAO
3. angle OBC
Answers
Answered by
0
Answer:
∡AOB=96
0
AB
:
BC
=3:2
⇒∡AOB:∡BOC=3:2
⇒
∡BOC
96
0
=
2
3
⇒∡BOC=
3
2
×96
0
=64
0
Now, Δ
"
OBC is isosceles [∵ OB=OC=r]
∴ ∡BOC+2∡OBC=180
0
⇒∡OBC=
2
180−64
=58
0
also Δ
"
AOB is isosceles [because OA=OB=r]
∴ ∡AOB+2∡OBA=180
0
⇒∡OBA=
2
180−96
=42
0
∴ ∡ABC=58
0
+42
0
=100
0
Step-by-step explanation:
In the given figure, the lengths of arcs AB and BC are in the ratio 3: 2.
If ∠ AOB=96
o
, find
∠ BOC
∠ ABC
Attachments:
Answered by
0
Step-by-step explanation:
XAOB=96
AB
:
BC
=3:2
4AOB:XBOC=3:2
*BOC
96
2
3
= 4BOC=
3
2
x96
=64
Now, A
11
OBC is isosceles [ OB=OC=r]
XBOC+2XOBC=180
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