Question

In the given figure, LFDA=85°
FDA-85°. LABC= 45 and LACB=40° prove that DF||AE
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Answer 1

hay mate ur answer:

in the fig angleBAD =angleABC + angleBCA

=45+40

=85 degrees

since angle FDA = angleBAD

THEREFORE

DF PARELLEL TO AE

alternate interior angles

hope u understand...!

Answer 2

Heya...!!!!

Here's your Answer..!

➡ In ∆ ABC,

=> Angle B + Angle C = Angle CAE ( Exterior Angle property of triangle)

=> 40°+45° = Angle CAE

=> 85°

Since, Angle D = Angle CAE

So, DF||AE

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✌✌ HOPE THIS HELPS!!✌✌