in the given figure line AB and CD intersect at O <BOC =36 degree..find <x <y and <z
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x=∠BOC=36° (vert.opp ∠s)
x+y=180° (linear pair)
36+y=180⇒y=180-36=144°
z=y (vert.opp∠s)
=144°
∴x=36°,y=144°,z=144°.
x+y=180° (linear pair)
36+y=180⇒y=180-36=144°
z=y (vert.opp∠s)
=144°
∴x=36°,y=144°,z=144°.
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