Question

in the given figure lines AB and CD intersect at O.if angle AOC+ angle BOE=70 and angle DOB=40,find the reflex angle EOC​

Answer 1

Answer:

ANSWER

Given:∠BOD=40 ∘

Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)

∠AOC=40 ∘

Also,∠AOC+∠BOE=70 ∘

⇒∠BOE=70 ∘

−∠AOC=70 ∘

−40 ∘

=30 ∘

We need to find reflex∠COE

Reflex∠COE=360 ∘

−∠COE

Now, ∠AOC+∠COE+∠BOE=180 ∘

⇒∠COE+(∠AOC+∠BOE)=180 ∘

⇒∠COE+(40 ∘

+30 ∘

)=180 ∘

⇒∠COE=180 ∘

−70 ∘

=110 ∘

Reflex∠COE=360 ∘

−110 ∘

=250 ∘

Maybe You Experience a bug I am sorry for this

I Hope it's Help you

Now this is good