In the given figure lines AB and CD intersections at O.If <AOC+<BOE=70 and <BoD=40.find <BOE and reflex <CoE
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ab and CD intersect at o
Angle AOC+BOE=70 degree
BOD=40degree
to find BOE and COE.
AOD+BOD=180 degree
x. + 40=180
x=180-40
x=140degree
AOC+BOE+COE=180
70+ x=180
x=180-70
x=110 degree
COE=110
AOC=BOD(v.o angle)
AOC=40 degree
AOC+BOE=70degree
40+BOE=70
BOE=70-40=30
boe=30
reflex COE
Aoc+BOE+AOB
70+180=250degree
Angle AOC+BOE=70 degree
BOD=40degree
to find BOE and COE.
AOD+BOD=180 degree
x. + 40=180
x=180-40
x=140degree
AOC+BOE+COE=180
70+ x=180
x=180-70
x=110 degree
COE=110
AOC=BOD(v.o angle)
AOC=40 degree
AOC+BOE=70degree
40+BOE=70
BOE=70-40=30
boe=30
reflex COE
Aoc+BOE+AOB
70+180=250degree
bharatsingh2003:
hi
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