Question

In the given figure, lines CA and CB,
touch the circle with centre D in A and
B. If _ ADB = 125° then
i. Find the measure of Z ACB
ii. Find the type of the quadrilateral
O ABCD​

Answer 1

Answer:

∠ADC=

2

1

∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=

2

1

×130=65

∘

Now, ADCB is cyclic quadrilateral ⇒

Sum of opposite Angles is 180

∘

∴∠ABC+∠ADC=180

∘

∠ABC+65=180

∘

∠ABC=115

∘

Answer 2

Answer:

ABC is 15 .... this is correct answer