In the given figure <BAC = 90° and AD⊥BC and <BAD = 50⁰ then find <ACD
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Step-by-step explanation:
<BAD+<DAC=90°=> <DAC=40°
In ∆ACD ,
<A+<D+<C=180°
40°+90°+<ACD=180°
So, <ACD=50°
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