In the given figure
<SQR = 75°, find <PQS
<PQS = 110°, Fing <RQS
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Answered by
2
Answer:
(i) From figure,
∠PQS + ∠SQR = 180° [Linear pair of angles]
⇒∠PQS + 75° = 180°
⇒ ∠PQS = 180°-75°
⇒ ∠PQS = 105°
(ii) From figure again,
∠PQS + ∠RQS = 180°
⇒ 110° + ∠RQS = 180°
∠RQS = 180°- 110°
∠RQS = 70°
Answered by
6
Answer:
angle SQR =75
angle PQS = ?
angle SQR +ANGLE PQS =PQR
75 + ANGLE PQS= 180
ANGLE PQS=180 -75
ANGLE PQS =105
ANGLE PQS +ANGLE RQS=ANGLE PQR
110 +ANGLE RQS=180
ANGLE RQS=180-110
ANGLE RQS=70
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