In the given figure, O is the centre of a circle and ABE is a straight line. Find x.
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Answered by
1
Answer:
From the figure,
∠OAC=22
∘
, O is the centre of the circle.
To find, ∠ADC=y
∠BOC=2×∠BAC=2×22
∘
=44
∘
(Angle at the centre=2×angle at any point on the remaining part of the circle)
∠AOC=180
∘
−∠BOC=180
∘
−44=136
∘
(∴ AOB is a straight line)
⇒ ∠ADC=
2
1
×∠AOC=
2
1
×136
∘
=68
∘
(Angle at any pt. on the remaining part of the circle=
2
1
×angle at the centre)
Answered by
4
Answer:
The value of x will be 250°
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