in the given figure,O is the centre of a circle and <AOC = 120°<br />Find <BDC
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Answer:
30°
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Let us consider a another point say E
Than EOC will be a right angled ∆ where E is the right angle.
Now, we know that , sum of adjacent Angle is 180°
so, angle AOC-X= 180°
120-X=180°
X=180°-120°
X=60°.
Now we know that angle E is 90°
the sum of a triangle is 180°
So,
60°+90°+C=180°
150°+C =180°
C= 180°-150°
C=30°
If C=30° ,D is also equal to 30° because they are vertical opposite angles are equal.
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