Question

Simplify this is exponential form

[ { (-1/3)^2}^-2]-1​

Answer 1

Answer:

$\huge{\boxed{\rm{\red{[{(-1/3)^2}^-2]-1=80}}}}$

Step-by-step explanation:

Given that :-

[ { (-1/3)^2}^-2]-1

=>[ { (1/9)^-2]-1

we know that a^-n=1/a^n

=>[ { 9}^2]-1

=>(81)-1

=>80

[ { (-1/3)^2}^-2]-1=80

or

[ { (-1/3)^2}^-2]-1

we know tht (a^m)^n=a^mn

=>[(-1/3)^2×2]-1

=>[(-1/3)^-4]-1

we know that a^-n=1/a^n

=>(-3)^4-1

=>81-1

=>80

[ { (-1/3)^2}^-2]-1=80