Question

In the given figure, O is the centre of a circle in
which ZAOC = 100°. Side AB of quad. OABC has
been produced to D/Then, ZCBD = ?
(b) 40°
(d) 80°
(a) 50°
(c) 25°
guyz pls ans. it fast​

Answer 1

we know that angle made by arc at the centre is double the angle made at any point on the circle........

so,angleade by major arcAC at center=2angleABC

,angle ABC=1/2(360-100)

=130

also,angleABc+AngleCBD=180

so,angleCBD=180-130=50

hope it helps you

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