Question

in the given figure O is the centre of circle EFGHK. EF= FG = GH .find the value of x
please dont give irrelevant answers​

Answer 1

Answer:

Step-by-step explanation:

this is the answer bro see this

Answer 2

Given:

Angle EKH=72°

To find:

The measure of x°

Solution:

The required measure of x° is 66°. (Option B)

We know that the angle made at the centre is double the one formed at the circumference.

So, angle EOH=2(angle EKH)

Angle EOH=2(72°)

Angle EOH=144°

Now, we know that EF=FG=GH.

Since these chords are equal, they divide the angle made at the circle's centre into three equal parts.

We will join OF and OG.

Now, in triangle EOF,

OE=OF (circle's radius)

So, angle OEF=angle OFE=x

Angle EOF=1/3(angle EOH)

Angle EOF=1/3×144°

Angle EOF=48°

Also, angle EOF+angle OEF+angle OFE=180°

Using the values,

48°+x+x=180°

2x=180°-48°

2x=132°

x=66°

Therefore, the required measure of x° is 66°.