Question

in the given figure O is the centre of the circle A B is diameter is equal to 12 cm and BC = 15 cm find the area of the shaded region​

Answer 1

Answer:

$\Huge\mathbb{ANSWER}$

_______________________

$\mathfrak\Red{AREA OF THE SEMICIRCLE - AREA OF THE TRIANGLE = AREA OF THE SHADED REGION}$

Answer 2

Answer:

How can BC(a chord) longer than Ab(a diameter).

A diameter is the longest chord.

I think AB=15 cm

BC=12 cm

U wrote the opposite.......

Step-by-step explanation:

Triangle ABC is a right triangle(angle formed in a semi-circle is 90 degrees)

AB=15 cm

BC=12 cm

AC=√(AB²-BC²)

AC=√225-144

AC=√81

AC=9 cm

Area of triangle ABC=1/2*b*h

Area=1/2*9*12

Area= 54 cm²

Now, area of semi-circle ACB:

πr²/2

(22/7*6*6)/2

=22/7*6*3

=22/7*18

=396 / 7

=56.57 cm²

Area of shaded region=Area of semicircle-area of triangle

Area of shaded region=56.57 cm²-54 cm²

=2.57 cm²