Question

In the given figure,O is the centre of the circle and AB is a chord of the circlr. If AOB = 70°, find ACB

Answer 1

Heya User,

--> The Angle subtended by an Arc at the center is double of that subtended at the major arc √√

=> If Angle AOB = 70°
=> Angle ACB = 1/2 * 70° = 35° √√

Hence, angle ACB = 35°

Answer 2

angle subtended by the chord and any point on the circle is always 1/2 of angle made by centre with chord
so,ACB=1/2AOB
ACB=1/2×70
=35°