Question

In the given figure, O is the centre of the circle and BA = AC. If ∠ABC = 50o, find ∠BOC and ∠BDC.

Answer 1

triangle ABC is an isosceles triangle angle abc is equal to 50 degrees therefore then angle ACB is equal to 50° because ab is equal to AC aise therefore triangle ABC is half of the triangle be versus therefore angle abc is equal to half of the angle OBC then angle OBC is equal to1/2 ×50

angle BOC = 25

triangle BOC is a isosceles triangle

Bo =oc

angle BOC = angle OCB

angle OCB = 25

angle ( BOC + OCB + OCB ) = 180

25 + 25+OCB = 180

50+OCB = 180

OCB = 180 - 50

OCB = 130

and opposite angles are equal

angle BDC = 130

Answer 2

Answer:

hope it helps you

Step-by-step explanation:

triangle ABC is an isosceles triangle angle abc is equal to 50 degrees therefore then angle ACB is equal to 50° because ab is equal to AC aise therefore triangle ABC is half of the triangle be versus therefore angle abc is equal to half of the angle OBC then angle OBC is equal to1/2 ×50

angle BOC = 25

triangle BOC is a isosceles triangle

Bo =oc

angle BOC = angle OCB

angle OCB = 25

angle ( BOC + OCB + OCB ) = 180

25 + 25+OCB = 180

50+OCB = 180

OCB = 180 - 50

OCB = 130

and opposite angles are equal

angle BDC = 130