Question

In the given figure, 'O' is the centre of the circle. Arc AB = Arc BC = Arc CD.
If OAB = 48°, find:
1. AOB
2.BOD
3.OBD​

Answer 1

In the given figure O is the centre of the circle.

1. AOB=84°

2. BOD=84°

3. OBD=48°

Stepwise explanation is given below:

- As it is given that,

arc AB= arc BC= arc CD.

OAB=48°.

- First join OB

OA = OB ......(radius of the circle)

- With the isocelar theoram

angle OAB= angle OBA=48°

- In the ΔAOB, By measuring

angle AOB=84°

- Now, angle BOD=1/2( arc BC+arc CD)

=1/2(84+84)

angle BOD=84°

- InΔ OBD, by measuring

angle OBD=48°