Question

in the given figure, O is the centre of the circle. the radius of the circle is 3.1 cm and PA is a tangent drawn to the circle from point P. if OP = x cm and AP = 6.2 cm, then find the value of x.

Answer 1

Answer:

Step-by-step explanation:by using pythagorus theorem

OP^2=AP^2+AO^2

OP^2=(6.2)^2 + (3.1)^2

OP^2=38.44 + 9.61

OP^2=48.05

OP= Square root(48.05)

OP=6.93

I hope it is helped you

Answer 2

x = 6.93   O is the centre of the circle. the radius of the circle is 3.1 cm and PA is a tangent drawn to the circle from point P. if OP = x cm and AP = 6.2 cm

Step-by-step explanation:

O is the centre of the circle. the radius of the circle is 3.1 cm

=> OA = 3.1 cm

OP = x cm

AP = 6.2cm

Applying Pythagorean theorem

OP²  = OA² + AP²

=> x² = 3.1² + 6.2²

=> x² = 3.1² + (3.1 *2)²

=> x² = 3.1² + 3.1² * 2²

=> x² =  3.1² (1 + 4)

=> x = 3.1√5

=> x = 6.93

Learn more:

the length of tangent to a circle which is 13cm distance from the ...

https://brainly.in/question/14791961

The square ABCD is inscribed in a circle of radius 1 unit.ABP is a ...

https://brainly.in/question/655203