in the given figure O is the centre of the circle the radius of the circle is 3.1 cm and PA is the tangent drawn to the circle from point P .if OP equal to X centimetre and AP equal to 6.2 CM then find the value of x
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Answer:
6.93 cm
Step-by-step explanation:
Hi,
Since PA is the tangent to the circle
∠OAP = 90°
Given AP = 6.2 cm
radius of the circle, OP = 3.1 cm
From triangle OAP, we get
OP² = AP² + OA²
⇒OP² = 3.1² + 6.2² = 3.1²(1 + 4) = 3.1²*√5
⇒OP = 3.1*√5 ≈ 6.93 cm
Hence , value of x is approximately 6.93 cm.
Hope, it helped !
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