In the given figure O is the centre of the circle where angle ABC=30°,angle BCO=20°and angle OCD=20°.Then find angle ODC.Those v who will solved this question wit proper solution he/she will be given 20 points by me and marked with brainliest.
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warrior10:
hii
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Answered by
20
Hey here is ur answer
in triangle DCB
m of angle d+m of angle c+ measure of angle b=180
m of angle b is 30
m of angle c is 20+20 =40
m of d is ?
so
30+40+d=180
70+d=180
d=180-70=110
now o is centre hence DO is angle bisector
therefore measure of ODC =ODB
therefore measure of ODB and ODC is equal to measure of D
hence measure of ODC is 55 degree
hope it helps!!!
in triangle DCB
m of angle d+m of angle c+ measure of angle b=180
m of angle b is 30
m of angle c is 20+20 =40
m of d is ?
so
30+40+d=180
70+d=180
d=180-70=110
now o is centre hence DO is angle bisector
therefore measure of ODC =ODB
therefore measure of ODB and ODC is equal to measure of D
hence measure of ODC is 55 degree
hope it helps!!!
answer of this will be in 60°,70°,80°,and 90°
u may be right and I may be wrong
answer is 80°but i also dont no how this anwer is correct
Answered by
16
Answer: 80 degree
Aoc is isoscales triangle
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