Question

the daily cost of hiring a plumber,y,to work x hours on a repair project can be modeled using a linear function. The plumber charges a fixed cost of $80 plus an additional cost of $45 per hour. The plumber works a maximum of 8 hours per day. for one day of work,what is the range of the function for this situation

Answer 1

Step-by-step explanation:

The daily cost of hiring a plumber,y,to work x hours on a repair project can be modeled using the linear function y=55x +75. The plumber charges a fixed cost of $75 plus sn additional cost of 55 per hour. The plumber works a maximum of 50 hours per

Answer 2

Given:

the daily cost of hiring a plumber, y, to work x hours on a repair project can be modelled using a linear function. The plumber charges a fixed cost of $80 plus an additional cost of $45 per hour. The plumber works a maximum of 8 hours per day.

To Find:

for one day of work, what is the range of the function for this situation

Solution:

It is given that the daily cost of hiring a plumber is y and he works for x hours on a project, he fixed his cost of $80 daily on which an additional cost of $45 per hour is added, so the linear equation for this situation will be

Y=45X+80

where y is the output that is the cost and x is the input of how many hours he works daily and 80 is the constant of this equation, it is also stated that he can work a maximum of 8 hours daily, so

$Y=45X+80 \\where, \\0\leq X\leq8$

So the range of the equation will be

from X=0 to X=8

At X=0,

Y=45*0+80

Y=80

At X=8,

Y=45*8+80

Y=440

So the range will be,

$80\leq Y\leq440$

Hence, the range of the function is [80,440].