Question

In the given figure. O is the centre of two
concentric circles of radil 5 cm and 3 cm. From
an external point P tangents PA and PB are
drawn to these circles. If PA - 12 cm then PB
is equal to


​

Answer 1

Step-by-step explanation:

in triangle oap oa is 5 and pa is 12 and right angle triangle therfore op = 13cm pythagoras theorem

in triangle opb op = 13 hypotenuse,

ob = 3

therefore base i.e pb = 13square = 3square + pbsquare

therefore PB =

$\sqrt{160}$

Answer 2

refer to the attachment for the detailed Answer

✨Hope it helps you✨

$\huge\mathfrak{Solution:}$

$\orange{OP:13cm}$

$\red{PB:√160cm}$ OR $\blue{PB:4√10cm}$