In the given figure, O is the mid-point of AC and BD, then
Angle A= Angle B
Angle A = Angle D
Angle B= Angle D
Angle D = Angle C
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O is mid point of AC and BD
hence AO = CO
and BO = DO
and angle DOC = angle BOA
thus triangle DOC similar to triangle BOA (by SAS)
angle B = angle D (corresponding angles of similar triangle)
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