In the given figure, O is the mid-point of PO, PS || TO Prove that APOS AROQ and hence prove that SO = OR
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We have,
△POS∼△ROQ
⇒ ∠3=∠4 and ∠1=∠2
Thus, PS and QR are two lines and the transversal PR cuts them in such a way that ∠3=∠4 i.e., alternate angles are equal.
Hence, PS∣∣QR.
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