In the given figure OA=3 cm OC=4 cm and AB = 12 cm find the perimeter of triangle ABC
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Given: OC = 4cm
OA = 3 cm
AC = 12 cm
By assuming ∠AOC = 90°
We Get AC = 5 cm (Pythagorous Theorum)
And ALso Assume That ∠BAC = 90°
We Get BC = 13 cm (pythagorous Theroum)
In ΔABC We Get AB=12 cm AC=5 cm BC=13cm
So AB + AC + BC = (12 + 5 + 13)cm = 30cm
OA = 3 cm
AC = 12 cm
By assuming ∠AOC = 90°
We Get AC = 5 cm (Pythagorous Theorum)
And ALso Assume That ∠BAC = 90°
We Get BC = 13 cm (pythagorous Theroum)
In ΔABC We Get AB=12 cm AC=5 cm BC=13cm
So AB + AC + BC = (12 + 5 + 13)cm = 30cm
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