Question

In the given figure oa=ob and op=oq prove that px =qx, ax =bx

Answer 1

Given:-OA=OB and OP=OQ

R.T.P:-i)PX=QX

ii)AX=BX

Proof:- In triangle PBO and AOQ

OB=OA (given)

OP=OA

<O=<O (common)

Therefore Triangle PBO ~ triangle QAO (S.A.S)

<B=<A (C.P.C.T)

In BXQ and AXP

<B=<A (proved above)

<BXQ=<AXP (V.O.A)

BQ=AP {OB-OQ=OA-OP}

triangle BXO ~ triangle AXP (A.A.S)

BX=AX

XQ=PX {C.P.C.T}

Answer 2

Step-by-step explanation:

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