Question

In the given figure, OABCD and EFGH are two squares of side 4 cm. If DZ = DS = 1cm. Then find the perimeter of the given figure ?​

Answer 1

Answer:

Area of square ABCD = Area of square AEFG = 16 cm2  Area of quadrant ADMB = 1 4 14 × π × (4)2 = 4π cm2   Radius of the smaller quadrant CPMQ = CM = AC – AM =4√2 - 4 = 4 ( √2 - 1) cm. ∴ Area of the smaller quadrant  Area of the shaded region inside the square ABCD  = Area of sq. ABCD – (Area of quadrant ADMB + Area of quadrant CPMQ)Read more on Sarthaks.com - https://www.sarthaks.com/964981/abcd-efga-are-squares-side-each-square-abcd-dmb-arcs-circles-with-centres-and-respectively

Step-by-step explanation: