in the given figure of a cube and cuboid which one has a greater surface area and by how much
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For the cuboid;
length, l = 15 cm
breadth, b = 6 cm
height, h = 2 cm
TSA(cuboid)
= 2(lb + bh + lh)
= 2(15x6 + 6x2 + 15x2)
= 2(90 + 12 + 30)
= 2(132)
= 264 cm² ... (i)
For the cube;
edge, a = 4 cm
TSA(cube)
= 6a²
= 6(4)²
= 6(16)
= 96 cm² ... (ii)
On comparing (i) and (ii)
TSA(cuboid) > TSA(cube)
Surface area of the cuboid is greater by
(264 - 96) cm²
= 168 cm²
Hence, surface area of cuboid is greater than that of cube and by 168 cm².
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