IN THE GIVEN FIGURE, Of IS THE CENTRE OF THE CIRCLE. MEASURE OF ANGLE BCO IS 30 DEGREES. FIND THE VALUE OF x AND y.
Answers
Since OD is parallel toBC
ANGLE DOC=ANGLE OCB(Alternate angles)
ANGLE DOC=30°
Now.
Angle AOC =90° +30°=120°
NOW angle ABD = 90°/2= 45°(Angle subtended by arcAD at the center is double of ANGLE subtended by it on circle).
Similarly,Taking arc AOC we can find
angle ABC =60°.
Now, y+45°=60°
y=60°-45°=15°
Applying angle sum law in Triangle ABE
90°+60° +x =180°
150°+x =. 180°
x = 180°-150°
x = 30°
Answer: y is equal to 15 degree and x is equal to 30 degree
Step-by-step explanation:
from the following diagram a d is a chord its substance 90 degree at the centre therefore it substance 90 degree by to which is equal to 45 degree at the circumference .
which implies angle abc is equal to 45 degree
from the following figure in triangle o u l C 90 degree + 30 degree + angle 1 is equal to 180 degree....
which implies angle 1 is equal to 60 degree
Angle 2 is equal to 30 degree ( by linear pair)
therefore chord CD September 30 degree at the centre.....
therefore acceptance 15 degree at angle DBC.....
therefore y is equal to 15 degree....
From the following diagram,
In triangle ALB,
90 degree + 45 degree + y + x is equal to 180 degree....
Where you will get x is equal to 30 degree
Therefore, found