Math, asked by SangeetaBhasin, 11 months ago

In the given figure of triangle ABC angle ABC=50 AC is extended to D and DE parallel to BA such that angle CDE=40. Find angle DCB.
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Answered by utkarshmishra9819

Answer:

angle cab = angle ead (interior alternate angles)

cab=40°

In triangke ABC

angle acb=180°-90°=90°

angke bcd +acb=180°(angkes on a straight line)

therefore Angle DCB=180°-90°=90°

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Answered by kaustubhborde

Step-by-step explanation:

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